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Revision #1 to TR06-085 | 13th December 2006 00:00

Using Quantum Oblivious Transfer for Cheat Sensitive Quantum Bit Commitment Revision of: TR06-085

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Abstract:
We investigate two-party cryptographic protocols, called cheat sensitive protocols, which guarantee that if one party cheats then the other has good probability of detecting the mistrustful party. We give quantum protocols for two basic cryptographic primitives: bit commitment and one-out-of-two oblivious transfer ($\binom{2}{1}$-OT), and prove that they are cheat sensitive. For the quantum bit commitment scheme we show that if a cheating gives $\varepsilon$ advantage i.e. information about the committed bit then the committer can detect the cheating with a probability $\Omega(\varepsilon^2)$; If the committer cheats trying to change his mind during the revealing phase then the probability of detecting the cheating is greater than some fixed constant $\lambda>0$. This improves the probabilities of cheating detections shown by Hardy and Kent [Phys.Rev.Lett.'04], as well as the scheme by Aharonov et~al.~[Proc. STOC'00] who presented a protocol that is sensitive against cheating by one party, but not both parties at the same time. Our cheat sensitive quantum $\binom{2}{1}$-OT protocol guarantees that if cheating gives any mistrustful party $\varepsilon$ advantage then the other party can detect the cheating with a probability $\Omega(\varepsilon^2)$. The heart of the both cheat-sensitive protocols is a weakened version of quantum $\binom{2}{1}$-OT which we call {\em susceptible} quantum $\binom{2}{1}$-OT. In this version, similarly as in the standard definition, Alice has initially secret bits $a_0,a_1$ and Bob has a secret selection bit $i$ and if both parties are honest they solve the $\binom{2}{1}$-OT problem fulfilling the standard security requirements. However, if Alice is dishonest and she gains some information about the secret selection bit then the probability that Bob computes the correct value is proportionally small. Moreover, if Bob is dishonest and he learns something about both bits, then he is not able to gain full information about one of them.

Paper:

TR06-085 | 15th May 2006 00:00

Using Quantum Oblivious Transfer to Cheat Sensitive Quantum Bit Commitment


Abstract:
It is well known that unconditionally secure bit commitment is impossible even in the quantum world. In this paper a weak variant of quantum bit commitment, introduced independently by Aharonov et al. and Hardy and Kent is investigated. In this variant, the parties require some nonzero probability of detecting a cheating, i.e. if Bob, who commits a bit $b$ to Alice, changes his mind during the revealing phase then Alice detects the cheating with a positive probability (we call this property binding); and if Alice gains information about the committed bit before the revealing phase then Bob discovers this with positive probability (sealing). In our paper we give quantum bit commitment scheme that is simultaneously binding and sealing and we show that if a cheating gives $\varepsilon$ advantage to a malicious Alice then Bob can detect the cheating with a probability $\Omega(\varepsilon^2)$. If Bob cheats then Alice's probability of detecting the cheating is greater than some fixed constant $\lambda>0$. This improves the probabilities of cheating detections shown by Hardy and Kent and the scheme by Aharonov et al. who presented a protocol that is either binding or sealing, but not simultaneously both. To construct a cheat sensitive quantum bit commitment scheme we use a protocol for a weak quantum one-out-of-two oblivious transfer ($\binom{2}{1}$-OT). In this version, similarly as in the standard definition, Alice has initially secret bits $a_0,a_1$ and Bob has a secret selection bit $i$ and if both parties are honest they solve the $\binom{2}{1}$-OT problem fulfilling the standard security requirements. However, if Alice is dishonest and she gains some information about the secret selection bit then the probability that Bob computes the correct value is proportionally small. Moreover, if Bob is dishonest and he learns something about both bits, then he is not able to gain full information about one of them.


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